Python 生成矩阵

限定步长，起始数字，然后生成x行，y列的矩阵

>>> def range2rect(x,y,start=0,step=1):
... 	N=[]
... 	F=[]
... 	for i in range(x):                  #等价于for(i=0,i<x,i++)
... 		for j in range(y):
... 			F.append(start)
... 			start += step
... 		N.append(F)
... 		F=[]
... 	return N
... 
>>> N=range2rect(3,4)
>>> N
[[0, 1, 2, 3], [4, 5, 6, 7], [8, 9, 10, 11]]

由一个元组形式生成矩阵

>>> def tuple2rect(tuple,x,y):
... 	res=[]
... 	row=count=0
... 	for i in tuple:
... 		count += 1
... 		res.append(i)
... 		if count%y ==0:
... 			yield res
... 			res=[]
... 			row += 1
... 		if row == x:		#一旦达到所要求的行数，就结束循环
... 			break
... 
>>> rect=[]
>>> for i in tuple2rect((1,2,3,3,4,5,5,6,7,8),2,3):
... 	rect.append(i)
... 
>>> rect
[[1, 2, 3], [3, 4, 5]]