【C语言编程技巧】快速访问结构体成员的一种方法

  3 struct p                                                                                        
  4 {   unsigned int id;                                                                            
  5     unsigned int age;                                                                           
  6     unsigned int sex;                                                                           
  7 };                                                                                              
  8                                                                                                 
  9                                                                                                 
 10 int main(void)                                                                                  
 11 {                                                                                               
 12                                                                                                 
 13     struct p *p1;                                                                               
 14                                                                                                 
 15     unsigned int *pp1;                                                                          
 16                                                                                                 
 17                                                                                                 
 18     p1 = malloc(sizeof(struct p));                                                              
 19     p1->id   = 3;                                                                               
 20     p1->age  = 22;                                                                              
 21     p1->sex  = 1;                                                                               
 22                                                                                                 
 23     pp1 = p1;                                                                                   
 24                                                                                                 
 25     printf("the pp1 is: 0x%x, the value is: 0x%x/n",pp1++,*pp1);                                
 26                                                                                                 
 27                                                                                                 
 28     printf("the pp1 is: 0x%x, the value is: 0x%x/n",pp1++,*pp1);                                
 29                                                                                                 
 30     printf("the pp1 is: 0x%x, the value is: 0x%x/n",pp1,*pp1);                                  
 31                                                                                                 
 32     _exit(0);                                                                                   
 33 }