分组查询
语法:
select 查询列表 列(要求出现在group by的后面) 5
from 表 1
【where 筛选条件】 2
group by 分组的字段 3
【having 分组后的筛选条件】 4
【order by 排序的字段】 6
分组查询的执行顺序:1——>2——>3——>4——>5——>6
注:(1)查询列表比较特殊,必须是分组函数和group by后面出现的字段(按谁分组,谁就可以被查询出来)
(2)分组查询中的筛选条件分为两类:(划分标准是他们的数据源不同)
分组前筛选:原始表 GROUP BY关键字前面 关键字:WHERE
分组后筛选:分组后的结果集 GROUP BY关键字后面 关键字:HAVING
注意:a.分组函数做条件肯定是放在HAVING子句中
b.能用分组前筛选时,就优先使用分组前筛选,因为它的效率更高
(3)GROUP BY子句支持单个字段分组,多个字段分组(多个字段之间用逗号隔开,没有顺序限制),也支持表达式和函 数
(4)也可以添加排序,排序放在分组查询的最后
1.简单使用
案例:查询每个工种的最高工资
SELECT MAX(salary),job_id
FROM employees
GROUP BY job_id
案例:查询每个位置上的部门个数:
SELECT COUNT(*),location_id
FROM departments
ORDER BY location_id
2.添加分组前的筛选
案例:查询邮箱中包含a字符的,每个部门的平均工资
SELECT AVG(salary),department_id
FROM employees
WHERE email like`%e%`
GROUP BY department_id
3.添加分组后的筛选(在查询后的结果进行处理)
案例一:查询那个部门的员工数大于2
要分为俩步来考虑:
(1)查询每个部门的员工个数
SELECT COUNT(*),department_id
FROM employees
GROUP BY department_id
(2)根据(1)的结果进行筛选,看哪个部门的大于2
SELECT COUNT(*),department_id
FROM employees
GROUP BY department_id
HAVING COUNT(*)>2
案例二:查询每个工种有奖金的员工的最高工资>12000的工种编号和最高工资
(1)查询每个工种有奖金的最高工资
SELECT MAX(salary),job_id
FROM employees
WHERE commission_pet IS NUT NULL
GROUP BY job_id
(2)根据(1)的结果继续进行筛选,最高工资>12000
SELECT MAX(salary),job_id
FROM employees
WHERE commission_pet IS NUT NULL
GROUP BY job_id
HAVING MAX(salary)>12000
案例三:查询领导编号>102的每个领导手下的最低工资>5000的领导编号是哪个,以及其最低工资
(1)查询每个领导下员工的最低工资
SELECT MIN(salary),manager
FROM employees
GROUP BY manager_id
(2)添加筛选条件:领导编号>102
SELECT MIN(salary),manager
FROM employees
WHERE manager_id>102
GROUP BY manager_id
(3)添加筛选条件:最低工资>5000
SELECT MIN(salary),manager
FROM employees
WHERE manager_id>102
GROUP BY manager_id
HAVING MIN(salary)>5000
4.按表达式或函数分组:
案例:按员工姓名的长度分组,查询每一组的员工个数,筛选员工个数>5的有哪些
(1)查询每个长度的员工个数
SELECT COUNT(*),LENGTH(last_name) length_name
FROM employees
GROUP BY LENGTH(last_name)
(2)添加筛选条件:
SELECT COUNT(*),LENGTH(last_name) length_name
FROM employees
GROUP BY LENGTH(last_name)
HAVING COUNT(*)>5
5.按多个字段分组:
案例:查询每个部门每个工种的员工的平均工资
SELECT AVG(salary),department_id,job_id
FROM employees
GROUP BY department_id,job_id
6.添加排序:
案例:查询每个部门每个工种的员工的平均工资,并按平均工资高低进行排序
SELECT AVG(salary),department_id,job_id
FROM employees
GROUP BY department_id,job_id
ORDER BY AVG(salary)
习题:
1.查询员工的最高工资与最低工资的差距(DIFFERENCE)
SELECT MAX(salary)-MIN(salary) DIFFERENCE
FROM employees
2.查询各个管理者手下员工的最低工资,其中最低工资不能低于6000,没有管理者的员工不能计算在内
SELECT MIN(salary),manager_id
FROM employees
WHERE manager IS NOT NULL
GROUP BY manager_id
HAVING MIN(salary)>=6000
3.查询所有部门的编号,员工数量和工资平均值,并按平均工资降序
SELECT COUNT(*), AVG(salary),department_id
FROM employees
GROUP BY depaertment_id
ORDER BY AVG(salary) DESC
4.选择具有各个job_id的员工人数
SELECT COUNT(*),job_id
FROM employees
GROUP BY job_id