#include<iostream>
using namespace std;
void merge(int* a, int* temp, int begin, int middle, int end){
int i = begin;
int j = middle + 1;
int k = 0;
while (i <= middle&&j <= end){//比较两个指针所指向的元素,选择相对小的元素放入到合并空间,并移动指针到下一位置
if (a[i] < a[j])
temp[k++] = a[i++];
else
temp[k++] = a[j++];
}
while (i <= middle)//若第一个序列有剩余,直接拷贝出来粘到合并序列尾
temp[k++] = a[i++];
while (j <= end)//若第二个序列有剩余,直接拷贝出来粘到合并序列尾
temp[k++] = a[j++];
for (i = 0; i < k; i++)//将排序好的序列拷贝回数组中
a[begin + i] = temp[i];
}
//递归版本
void merge_sort_recurse(int* a, int* temp, int begin, int end){
int middle = (begin + end) >> 1;
if (begin < end){
merge_sort_recurse(a, temp, begin, middle);//左边有序
merge_sort_recurse(a, temp, middle + 1, end);//右边有序
merge(a, temp, begin, middle, end);//再将两个有序数列合并
}
}
//非递归版本,将a中相邻长度为s的子序列两两归并
void merge_pass(int* a, int* temp, int s, int len){
int i = 0;
int j;
while (i < len - 2 * s + 1){
merge(a, temp, i, i + s - 1, i + 2 * s - 1);
i += 2 * s;
}
if (i < len - s + 1)//归并最后两个序列
merge(a, temp, i, i + s - 1, len);
}
void merge_sort_no_recurse(int* a, int len){
int temp[1001];
int k = 1;
while (k <= len){
merge_pass(a, temp, k, len);
k *= 2; //子序列长度加倍
}
}
int main(){
int num1[1001] = { 50, 10, 90, 30, 70, 40, 80, 60, 20 };
int temp1[1001];
int num2[1001] = { 50, 10, 90, 30, 70, 40, 80, 60, 20 };
int n = 9;
merge_sort_recurse(num1, temp1, 0, n-1);
for (int i = 0; i < n; i++)
cout << num1[i] << " ";
cout << endl;
merge_sort_no_recurse(num2, n - 1);
for (int i = 0; i < n; i++)
cout << num2[i] << " ";
cout << endl;
return 0;
}
【排序】归并排序(递归和非递归版本)
最新推荐文章于 2025-03-09 16:24:20 发布