/**
* 作业:汉诺塔递归算法
* Created by rgl on 2018/10/29.
*/
public class Hanoilmpl {
public void hanoi(int n, char A, char B, char C) {
if (n == 1) {
move(A, C);
} else {
hanoi(n - 1, A, C, B);//步骤1 按ACB数序执行N-1的汉诺塔移动
move(A, C); //步骤2 执行最大盘子移动
hanoi(n - 1, B, A, C);//步骤3 按BAC数序执行N-1的汉诺塔移动
}
}
private void move(char A, char C) {//执行最大盘子的从A-C的移动
System.out.println("move:" + A + "--->" + C);
}
public static void main(String[] args) {
Hanoilmpl hanoi = new Hanoilmpl();
System.out.println("移动汉诺塔的步骤:");
hanoi.hanoi(3, 'a', 'b', 'c');
}
}
/**运行结果
移动汉诺塔的步骤:
move:a--->c
move:a--->b
move:c--->b
move:a--->c
move:b--->a
move:b--->c
move:a--->c
Process finished with exit code 0