老规矩,官方代码:作者:LeetCode-Solution
链接:https://leetcode-cn.com/problems/remove-nth-node-from-end-of-list/solution/shan-chu-lian-biao-de-dao-shu-di-nge-jie-dian-b-61/
来源:力扣(LeetCode)
个人微改:
import java.util.*;
class ListNode{
int val;
ListNode next;
ListNode() {}
ListNode(int val){this.val=val;}
ListNode(int val,ListNode next){this.val = val;this.next=next;}
public void addNode(int e) {
ListNode newNode = new ListNode(e);
if(this.next==null) {
this.next = newNode;
}else {
this.next.addNode(e);
}
}
public ListNode remove(ListNode head,int n) {
ListNode rookie = new ListNode(0,head);
int length = getLength(head);
ListNode cur = rookie;
for(int i=1;i<length-n+1;i++) {
cur = cur.next;
}
cur.next = cur.next.next;
ListNode ans = rookie.next;
return ans;
}
public int getLength(ListNode head) {
int length = 0;
while(head!=null) {
++length;
head = head.next;
}
return length;
}
public void print() {
System.out.print(this.val);
if(this.next!=null) {
System.out.print("-->");
this.next.print();
}
}
}
public class deleteLinkList {
public static void main(String args[]) {
ListNode L1 = new ListNode();
System.out.println("please enter the linked list capacity :");
Scanner sc = new Scanner(System.in);
int m = sc.nextInt();
int a[] = new int[m];
System.out.println("please enter the data of your linked list :");
for(int i=0;i<m;i++) {
a[i]=sc.nextInt();
L1.addNode(a[i]);
}
System.out.println("please enter the number of reciprocal of the list you want to delete :");
int n = sc.nextInt();
L1.remove(L1.next,n);
L1.next.print();
sc.close();
}
}
测试结果:
please enter the linked list capacity :
5
please enter the data of your linked list :
1 2 3 4 5
please enter the number of reciprocal of the list you want to delete :
2
1-->2-->3-->5
本文讲解了如何使用Java实现LeetCode中的删除链表倒数第N个节点问题,通过ListNode类实现链表操作,包括添加节点、获取链表长度和删除指定位置节点。示例代码详细展示了整个过程,适合初学者理解链表操作技巧。
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