其实,这个问题很简单 ,可偏偏很多人不知道,于是写了这个
先用2进制方式打开文件,读出数据到byte数组中,然后用copymemory去掉文件头(头两个字符分别是FF FE(16进制))得到一个新的byte数组,最后利用strconv函数即可,下面给出代码:
Option Explicit
Private Declare Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" (Destination As Any, source As Any, ByVal Length As Long)
Private Function ReadUniFile(ByVal sFile As String) As String
'没加错误处理,大家自己加吧
Dim a As Long
a = FileLen(sFile)
ReDim buff(a - 1) As Byte
ReDim buff1(a - 3) As Byte
Open sFile For Binary As #1
Get #1, , buff
Close #1
CopyMemory buff1(0), buff(2), a - 2
Dim s As String
s = StrConv(buff1, vbNarrow)
ReadUniFile = s
End Function
先用2进制方式打开文件,读出数据到byte数组中,然后用copymemory去掉文件头(头两个字符分别是FF FE(16进制))得到一个新的byte数组,最后利用strconv函数即可,下面给出代码:
Option Explicit
Private Declare Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" (Destination As Any, source As Any, ByVal Length As Long)
Private Function ReadUniFile(ByVal sFile As String) As String
'没加错误处理,大家自己加吧
Dim a As Long
a = FileLen(sFile)
ReDim buff(a - 1) As Byte
ReDim buff1(a - 3) As Byte
Open sFile For Binary As #1
Get #1, , buff
Close #1
CopyMemory buff1(0), buff(2), a - 2
Dim s As String
s = StrConv(buff1, vbNarrow)
ReadUniFile = s
End Function