处理大整数

目的：利用BigInteger类提供的任意精度的整数计算，实现大整数之间的加减乘除算法，同时求出给定的大整数因子。

实验代码

import java.math.BigInteger;

public class HandleBigInteger {


    public static void main(String args[]) {
        BigInteger n1 = new BigInteger("987654321987654321987654321");
        BigInteger n2 = new BigInteger("123456789123456789123456789");
        BigInteger result = null;
        result = n1.add(n2);//n1和n2做加法运算
        System.out.println("和:" + result.toString());
        result = n1.subtract(n2);//n1和n2做减法运算
        System.out.println("差:" + result.toString());
        result = n1.multiply(n2);//n1和n2做乘法运算
        System.out.println("积:" + result.toString());
        result = n1.divide(n2);//n1和n2做除法运算
        System.out.println("商:" + result.toString());
        BigInteger m = new BigInteger("1968957"),
                COUNT = new BigInteger("0"),
                ONE = new BigInteger("1"),
                TWO = new BigInteger("2");
        System.out.println(m.toString() + "的因子有:");
        for (BigInteger i = TWO; i.compareTo(m) < 0; i = i.add(ONE)) {
            if ((n1.remainder(i).compareTo(BigInteger.ZERO)) == 0) {
                COUNT = COUNT.add(ONE);
                System.out.print("     " + i.toString());
            }
        }
        System.out.println("");
        System.out.println(m.toString() + "一共有" + COUNT.toString() + "个因子");

    }
}

运行结果