编写一个程序，输入年份和月份，判断该年是否是闰年，并根据给出的月份判断是什么季节和该月有多少天？（闰年的条件是年份能被4整除但不能被100整除，或者能被400整除；规定3~5月为春季，6~8月为夏季，

编写一个程序，输入年份和月份，判断该年是否是闰年，并根据给出的月份判断是什么季节和该月有多少天？（闰年的条件是年份能被4整除但不能被100整除，或者能被400整除；规定3_{5月为春季，6}8月为夏季，9~11月为秋季，1、2和12月为冬季）。

**输入格式要求："%d,%d" 提示信息：“Please enter year,month:”
**输出格式要求："%d is leap year\n" “%d is not leap year\n” “The season is spring\n” “The season is summer\n” “The season is autumn\n” “The season is winter\n” “The number of days of this month is %d\n”
程序运行示例如下：
实例1：
Please enter year,month:2012,11
2012 is leap year
The season is autumn
The number of days of this month is 30
实例2：
Please enter year,month:2013,12
2013 is not leap year
The season is winter
The number of days of this month is 31

#include <stdio.h>
#include <stdlib.h>
int kunkun(int b);
void test(int b);
int a, b;
int main()
{
    printf("Please enter year,month:");
    scanf("%d,%d", &a, &b);
    if(a % 4 == 0&&a % 100 != 0)
    {
        printf("%d is leap year\n", a);
        kunkun(b);
        test(b);
    }else if(a % 400 == 0)
    {
        printf("%d is leap year\n", a);
        kunkun(b);
        test(b);
    }else
    {
        printf("%d is not leap year\n", a);
        kunkun(b);
        test(b);
    }

    return 0;
}
int kunkun(int b)
{
    if(3 <= b&&b <= 5)
        {
            printf("The season is spring\n");
        }else if(6 <= b&&b <= 8)
        {
            printf("The season is summer\n");
        }else if(9 <= b&&b <= 11)
        {
            printf("The season is autumn\n");
        }else
        {
            printf("The season is winter\n");
        }
}
void test(int b)
{
    int arr[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
    if (a % 4 == 0&&a % 100 != 0&&b == 2)
    {
        printf("The number of days of this month is %d\n", 29 );
    }else if(a % 400 == 0&&b == 2)
    {
        printf("The number of days of this month is %d\n", 29);
    }else
    {
        printf("The number of days of this month is %d\n", arr[b-1]);
    }
}