C语言是一门 结构化 的程序设计语言
1、顺序结构 2、选择结构 3、循环结构
分支语句; if语句、switch语句
循环语句: while for do while go to
#include<stdio.h>
int main()
{
int ret = 0;
int ch = 0;
char password[20] = { 0 };
printf("请输入密码:->");
scanf("%s", password);//输入密码,并存放在password数组中
//缓冲区还剩一个'\n'
//读取一下'\n'
while ((ch=getchar()) != '\n')
{
;
}
printf("确认密码(Y/N):->");
ret=getchar();
if (ret == 'Y')
printf("完成确认!");
else
printf("放弃确认!");
return 0;
}

while 语句
#include<stdio.h>
int main()
{
int ch = 0;
while ((ch = getchar()) != EOF)
{
if (ch < '0'|| ch>'9')
continue;
putchar(ch);
}
return 0;
}
输出0-9的数字
for语句(continue与break区别)
#include<stdio.h>
int main()
{
int i;
for (i = 1; i <= 10; i++)
{
if (i == 5)
continue ;
printf("%d\n", i);
}
return 0;
}
代码实现

#include<stdio.h>
int main()
{
int i;
for (i = 1; i <= 10; i++)
{
if (i == 5)
break ;
printf("%d\n", i);
}
return 0;
}

do while 语句(continue与break区别)
#include<stdio.h>
int main()
{
int num = 1;
do
{
if (num == 5)
continue;
printf("num=%d\n", num);
num++;
} while (num <= 10);
return 0;
}

#include<stdio.h>
int main()
{
int num = 1;
do
{
if (num == 5)
break;
printf("num=%d\n", num);
num++;
} while (num <= 10);
return 0;
}

计算n!
#include<stdio.h>
int main()
{
int i = 0;
int n = 0;
int ret = 1;
scanf("%d", &n);
for (i = 1; i <= n; i++)
{
ret = ret*i;
}
printf("ret=%d\n", ret);
return 0;
}

计算1!+2!+3!+……+10!
#include<stdio.h>
int main()
{
int i = 0;
int n = 0;
int ret = 1;
int sum = 0;
for (n = 1; n <= 10; n++)
{
//ret必须起始值=1
ret = 1;
for (i = 1; i <= n; i++)
{
ret = ret*i;
}
sum = sum + ret;
}
printf("sum=%d\n", sum);
return 0;
}

代码改进
int main()
{
int n = 0;
int i = 0;
int ret = 1;
int sum = 0;
for (n = 1; n <= 10; n++)
{
ret = ret*n;
sum = sum + ret;
}
printf("sum=%d\n",sum);
return 0;
}
有序数组中查找具体的某个数字
#include<stdio.h>
//遍历算法
int main()
{
int i = 0;
int arr[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
int sz = sizeof(arr) / sizeof(arr[0]);
int k = 7;
for(i = 0; i < sz; i++)
{
if (k ==arr[i])
{
printf("找到了,下标为%d\n", i);
break;
}
if (i==sz)
{
printf("找不到!");
}
}
return 0;
}
代码改进
#include<stdio.h>
int main()
//二分查找算法
{
int arr[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
int left= 0;
int k = 7;
int sz = sizeof(arr)/sizeof(arr[0]);
int right = sz-1;
while (left<=right)
{
int mid = (right + left) / 2;
if (arr[mid] > k)
{
left = 0;
right = mid - 1;
}
else if (arr[mid] < k)
{
left = mid + 1;
right = sz - 1;
}
else
{
printf("找到了,下标为:%d\n",mid);
break;
}
}
if (left > right)
{
printf("找不到\n");
}
return 0;
}

演示多个字符从两端移动,向中间汇集
#include<stdio.h>
#include<string.h>
#include<windows.h>
int main()
{
char arr1[] = { "beautiful queen" };
char arr2[] = { "***************" };
int left = 0;
int right = strlen(arr1) - 1;
while (left <= right)
{
arr2[left] = arr1[left];
arr2[right] = arr1[right];
printf("%s\n", arr2);
//打印休息一秒
Sleep(1000);
left++;
right--;
}
return 0;
}

当然代码还可以改进在Sleep(1000);后再加上语句system(cls)引用头文件#include<stdlib.h>可以每执行一次清屏,在执行下一次
模拟用户登录情景,并且只能登陆三次。(只允许输入三次密码,密码正确则登陆成功,密码错误,则退出程序)
#include<stdio.h>
#include<string.h>
int main()
{
int i = 0;
char password[20] = { 0 };
for (i = 0; i < 3; i++)
{
printf("请输入密码:->");
scanf("%s", password);
if (strcmp(password, "123456")==0)
{
printf("密码正确!\n");
break;
}
else
{
printf("密码错误,请重新输入!\n");
}
}
if (i == 3)
{
printf("三次密码错误,退出程序!\n");
}
return 0;
}
