灮星的博客

9.回文数Tips题目代码代码一代码二 Tips 1. Once we need to reverse a number and use the way of: rev = rev * 10 + temp % 10; We have to think if the reverse of the given number will overflow when multiplied by 10. 2. To employ the method of Math: if a number is a Palind

整数反转题目代码代码一代码二 题目 代码 代码一 int reverse(int x){ int rst = 0; while(x){ if(rst < INT_MIN / 10 + x % 10 / 10 || rst > INT_MAX / 10 + x % 10 / 10){ //(x % 10 / 10)is always equal to zero, which can be omitted.