D相乘(蓝桥杯)

设该数为$x$，$x÷1000000007$的商为$k$，则有方程$x\ast 2021=k\ast 1000000007+999999999,k\in N$

$x=\frac{k\ast 1000000007+999999999}{2021}$

k = 0
while True:
	if (k*1000000007+999999999)%2021==0:
		print(k)
		break
	k += 1