柱状图中最大的矩形
给定 n 个非负整数,用来表示柱状图中各个柱子的高度。每个柱子彼此相邻,且宽度为 1
求在该柱状图中,能够勾勒出来的矩形的最大面积。
示例 1:
输入:heights = [2,1,5,6,2,3]
输出:10
解释:最大的矩形为图中红色区域,面积为 10
示例 2:
输入: heights = [2,4]
输出: 4
题解:
func largestRectangleArea(heights []int) int {
n := len(heights)
left, right := make([]int, n), make([]int, n)
mono_stack := []int{}
for i := 0; i < n; i++ {
for len(mono_stack) > 0 && heights[mono_stack[len(mono_stack)-1]] >= heights[i] {
mono_stack = mono_stack[:len(mono_stack)-1]
}
if len(mono_stack) == 0 {
left[i] = -1
} else {
left[i] = mono_stack[len(mono_stack)-1]
}
mono_stack = append(mono_stack, i)
}
mono_stack = []int{}
for i := n - 1; i >= 0; i-- {
for len(mono_stack) > 0 && heights[mono_stack[len(mono_stack)-1]] >= heights[i] {
mono_stack = mono_stack[:len(mono_stack)-1]
}
if len(mono_stack) == 0 {
right[i] = n
} else {
right[i] = mono_stack[len(mono_stack)-1]
}
mono_stack = append(mono_stack, i)
}
ans := 0
for i := 0; i < n; i++ {
ans = max(ans, (right[i] - left[i] - 1) * heights[i])
}
return ans
}