7-30 念数字 (15 分)

题目详情 (pintia.cn)

code1

#include<stdio.h>
int main(){
	char a;
	int cnt=0;
	while(++cnt){
		a=getchar();
		if(a=='\n')break;
		if(cnt!=1) printf("*");
		switch(a){
			case('0'):printf("ling");break;
			case('1'):printf("yi");break;
			case('2'):printf("er");break;
			case('3'):printf("san");break;
			case('4'):printf("si");break;
			case('5'):printf("wu");break;
			case('6'):printf("liu");break;
			case('7'):printf("qi");break;
			case('8'):printf("ba");break;
			case('9'):printf("jiu");break;
			case('-'):printf("fu");break;
		}
	}
    return 0;
}

简单粗暴，读入一个数，读出一个数 。

code2

#include<stdio.h>
int main(){
	char a[10][10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    int b[10]={0};
    int i,j,n;
    scanf("%d",&n);
		if(n<0){
	    	printf("fu ");
	    	n=-n;
		} 
	    for(i=0;n;i++){
	    	b[i]=n%10;
	    	n/=10;
		}
		for(j=i-1;j>0;j--){
            printf("%s ",a[b[j]]);
		}
		printf("%s",a[b[0]]);
    return 0;
}

把输入的数字，放在数组中，倒序输出数字 

code3

#include<stdio.h>
#include<string.h>
int main(){
	int i;
	char a[10][10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    char b[10];
    scanf("%s",b);
    if(b[0]=='-'){
    	printf("fu");
	}else{
		printf("%s",a[b[0]-'0']);
	}
	for(i=1;i<strlen(b);i++){
		printf(" %s",a[b[i]-'0']);
	}
    return 0;
}

这个是网上看的，比较巧，把输入的数字，直接看成字符串。利用字符串的序列，正序直接输出读数。下面思路一样，利用指针：

#include<stdio.h>
int main(){
    char a[10];
    char b[][10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu",};
    scanf("%s",&a);
    char* p= a;
    while(*p!='\0'){
    	if(*p=='-') printf("fu");
    	else{
    		printf("%s",b[*p-'0']);
		}
		if(*(p+1)!='\0') printf("*");
		p++;
	}
    return 0;
}