LeetCode 214. 最短回文串
Manacher算法
const int N = 1e5 + 10;
class Solution {
public:
char str[N];
int p[N];
int n;
int maxlen = 0;
void init(string s)
{
n = 0;
str[n ++] = '$';
str[n ++] = '#';
for(int i = 0; i < s.size(); i ++)
str[n ++] = s[i], str[n ++] = '#';
str[n ++] = '^';
}
int manacher()
{
int mid = 0, mr = 0;
for(int i = 1; i < n; i ++)
{
if(i < mr) p[i] = min(p[2 * mid - i], mr - i);
else p[i] = 1;
while(str[i + p[i]] == str[i - p[i]])
p[i] ++;
if(p[i] + i > mr)
{
mr = p[i] + i;
mid = i;
}
maxlen = max(maxlen, p[i] - 1);
}
return mid;
}
string shortestPalindrome(string s) {
init(s);
cout << str << endl;
int mid = manacher();
// cout << maxlen << endl;
int pre_max = 0;
for(int i = 0; i < n; i ++)
if(p[i] == i)
pre_max = i;
cout << pre_max - 1 <<endl;
string t = s.substr(pre_max - 1);
reverse(t.begin(), t.end());
s = t + s;
return s;
}
};
字符串Hash
const int N = 1e5 + 10;
typedef unsigned long long ULL;
class Solution {
public:
ULL p[N], pow = 131;
string shortestPalindrome(string s) {
int n = s.size();
p[0] = 1;
for(int i = 1; i < n; i ++)
p[i] = p[i - 1] * pow;
ULL sin = 0, cos = 0; //正向hash值和反向hash值一样则为回文串
int maxstr = -1;
for(int i = 0; i < n; i ++)
{
sin = sin * pow + s[i];
cos = cos + s[i] * p[i];
// cout << sin <<" " << cos << endl;
if(sin == cos)
maxstr = i;
}
string t = s.substr(maxstr + 1);
// cout << t << endl;
reverse(t.begin(), t.end());
return t + s;
}
};