在表的连接查询方面有一种现象被称为:笛卡尔积现象
案例:找出每一个员工的部门名称,要求显示员工名和部门名。
EMP表:
mysql> select * from emp;
+-------+--------+-----------+------+------------+---------+---------+--------+
| EMPNO | ENAME | JOB | MGR | HIREDATE | SAL | COMM | DEPTNO |
+-------+--------+-----------+------+------------+---------+---------+--------+
| 7369 | SMITH | CLERK | 7902 | 1980-12-17 | 800.00 | NULL | 20 |
| 7499 | ALLEN | SALESMAN | 7698 | 1981-02-20 | 1600.00 | 300.00 | 30 |
| 7521 | WARD | SALESMAN | 7698 | 1981-02-22 | 1250.00 | 500.00 | 30 |
| 7566 | JONES | MANAGER | 7839 | 1981-04-02 | 2975.00 | NULL | 20 |
| 7654 | MARTIN | SALESMAN | 7698 | 1981-09-28 | 1250.00 | 1400.00 | 30 |
| 7698 | BLAKE | MANAGER | 7839 | 1981-05-01 | 2850.00 | NULL | 30 |
| 7782 | CLARK | MANAGER | 7839 | 1981-06-09 | 2450.00 | NULL | 10 |
| 7788 | SCOTT | ANALYST | 7566 | 1987-04-19 | 3000.00 | NULL | 20 |
| 7839 | KING | PRESIDENT | NULL | 1981-11-17 | 5000.00 | NULL | 10 |
| 7844 | TURNER | SALESMAN | 7698 | 1981-09-08 | 1500.00 | 0.00 | 30 |
| 7876 | ADAMS | CLERK | 7788 | 1987-05-23 | 1100.00 | NULL | 20 |
| 7900 | JAMES | CLERK | 7698 | 1981-12-03 | 950.00 | NULL | 30 |
| 7902 | FORD | ANALYST | 7566 | 1981-12-03 | 3000.00 | NULL | 20 |
| 7934 | MILLER | CLERK | 7782 | 1982-01-23 | 1300.00 | NULL | 10 |
+-------+--------+-----------+------+------------+---------+---------+--------+
DEPT表:
mysql> select * from dept
-> ;
+--------+------------+----------+
| DEPTNO | DNAME | LOC |
+--------+------------+----------+
| 10 | ACCOUNTING | NEW YORK |
| 20 | RESEARCH | DALLAS |
| 30 | SALES | CHICAGO |
| 40 | OPERATIONS | BOSTON |
+--------+------------+----------+
下面的查询语句就造成了笛卡尔积现象,这里也使用了别名,emp e,dept d,使用别名的好处是:执行效率高,可读性好。
mysql> select e.ename,d.dname from emp e,dept d;
+--------+------------+
| ename | dname |
+--------+------------+
| SMITH | ACCOUNTING |
| SMITH | RESEARCH |
| SMITH | SALES |
| SMITH | OPERATIONS |
| ALLEN | ACCOUNTING |
| ALLEN | RESEARCH |
| ALLEN | SALES |
| ALLEN | OPERATIONS |
| WARD | ACCOUNTING |
| WARD | RESEARCH |
| WARD | SALES |
| WARD | OPERATIONS |
| JONES | ACCOUNTING |
| JONES | RESEARCH |
| JONES | SALES |
| JONES | OPERATIONS |
| MARTIN | ACCOUNTING |
| MARTIN | RESEARCH |
| MARTIN | SALES |
| MARTIN | OPERATIONS |
| BLAKE | ACCOUNTING |
| BLAKE | RESEARCH |
| BLAKE | SALES |
| BLAKE | OPERATIONS |
| CLARK | ACCOUNTING |
| CLARK | RESEARCH |
| CLARK | SALES |
| CLARK | OPERATIONS |
| SCOTT | ACCOUNTING |
| SCOTT | RESEARCH |
| SCOTT | SALES |
| SCOTT | OPERATIONS |
| KING | ACCOUNTING |
| KING | RESEARCH |
| KING | SALES |
| KING | OPERATIONS |
| TURNER | ACCOUNTING |
| TURNER | RESEARCH |
| TURNER | SALES |
| TURNER | OPERATIONS |
| ADAMS | ACCOUNTING |
| ADAMS | RESEARCH |
| ADAMS | SALES |
| ADAMS | OPERATIONS |
| JAMES | ACCOUNTING |
| JAMES | RESEARCH |
| JAMES | SALES |
| JAMES | OPERATIONS |
| FORD | ACCOUNTING |
| FORD | RESEARCH |
| FORD | SALES |
| FORD | OPERATIONS |
| MILLER | ACCOUNTING |
| MILLER | RESEARCH |
| MILLER | SALES |
| MILLER | OPERATIONS |
+--------+------------+
56 rows in set (0.00 sec)
怎么避免笛卡尔积现象? 当然是加条件过滤了 where
——思考:避免了笛卡尔积现象,会减少记录的匹配次数嘛?
————不会!次数还是56次,只不过显示记录过滤成了有效记录。
案例:找出每一个队员的部门名称,要求显示员工名和部门名。
mysql> select
e.ename ,d.dname
from
emp e,dept d
where
e.deptno = d.deptno;//sql92 以后不用。
+--------+------------+
| ename | dname |
+--------+------------+
| SMITH | RESEARCH |
| ALLEN | SALES |
| WARD | SALES |
| JONES | RESEARCH |
| MARTIN | SALES |
| BLAKE | SALES |
| CLARK | ACCOUNTING |
| SCOTT | RESEARCH |
| KING | ACCOUNTING |
| TURNER | SALES |
| ADAMS | RESEARCH |
| JAMES | SALES |
| FORD | RESEARCH |
| MILLER | ACCOUNTING |
+--------+------------+