实验要求:
实验拓扑图:
1、 配置ipv4公网
r2
[r2]int g0/0/1
[r2-GigabitEthernet0/0/1]ip add 23.1.1.1 24
r3
[r3]int g0/0/0
[r3-GigabitEthernet0/0/0]ip add 23.1.1.2 24
[r3-GigabitEthernet0/0/0]int lo0
[r3-LoopBack0]ip add 3.3.3.3 24
[r3-LoopBack0]int g0/0/1
[r3-GigabitEthernet0/0/1]ip add 34.1.1.1 24
r4
[r4]int g0/0/0
[r4-GigabitEthernet0/0/0]ip add 34.1.1.2 24
2、 配置ipv4私网
r1
[r1]int lo0
[r1-LoopBack0]ip add 192.168.1.1 25
[r1-LoopBack0]int lo1
[r1-LoopBack1]ip add 192.168.1.129 25
[r1-LoopBack1]int g0/0/1
[r1-GigabitEthernet0/0/1]ip add 192.168.0.1 30
r2
[r2]int g0/0/0
[r2-GigabitEthernet0/0/0]ip add 192.168.0.2 30
3、ipv4网通
r4上配置缺省
[r4]ip route-static 0.0.0.0 0 34.1.1.1
r2上配置缺省
[r2]ip route-static 0.0.0.0 0 23.1.1.2
此时 r2 可以 ping 通 r4
r1上配置静态缺省
[r1]ip route-static 0.0.0.0 0.0.0.0 192.168.0.2
r2
[r2]ip route-static 192.168.1.0 24 192.168.0.1
[r2]acl 2000
[r2-acl-basic-2000]rule permit source 192.168.0.0 0.0.255.255
[r2-acl-basic-2000]int g0/0/1
[r2-GigabitEthernet0/0/1]nat outbound 2000
4、r1 r2 上配置ipv6地址
r2
[r2]ipv6
[r2]int lo0
[r2-LoopBack0]ipv6 enable
[r2-LoopBack0]ipv6 add 2002:1701:0101:0000::1/64
r1
[r1]ipv6
[r1]int g0/0/1
[r1-GigabitEthernet0/0/1]ipv6 enable
[r1-GigabitEthernet0/0/1]ipv6 address 2002:1701:0101:0001::1/64
r2
[r2]int g0/0/