思路:
用队列完成,比较简单
struct TreeNode {
int val;
TreeNode* left;
TreeNode* right;
TreeNode(int x):val(x),left(NULL),right(NULL){}
};
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
vector<vector<int>> result;
queue<TreeNode*> que;
if (root != NULL) {
que.push(root);
}
while (!que.empty()) {
int size = que.size();
vector<int> path;
for (int i = 0; i < size;i++) {
TreeNode* Node = que.front();
que.pop();
path.push_back(Node->val);
if (Node->left)que.push(Node->left);
if (Node->right)que.push(Node->right);
}
result.push_back(path);
}
return result;
}
};
int main() {
TreeNode* A = new TreeNode(3);
TreeNode* B = new TreeNode(9);
TreeNode* C = new TreeNode(20);
TreeNode* D = new TreeNode(15);
TreeNode* E = new TreeNode(7);
A->left = B;
A->right = C;
C->left = D;
C->right = E;
Solution ss;
vector<vector<int>> res = ss.levelOrder(A);
for (auto& chs : res) {
for (auto& ch : chs) {
cout << ch << " ";
}
cout << endl;
}
return 0;
}