【python随笔】之【两个线程交替打印数字（线程的事件与通信）】

import threading
import time


def go1():
    with con:  # 先运行，先锁定
        for i in range(0, 10, 2):
            time.sleep(1)
            print(threading.current_thread().name, i)
            con.wait()  # 等待
            con.notify()  # 通知打印完成


def go2():
    with con:  # 后运行，等待解锁
        for i in range(1, 10, 2):
            time.sleep(1)
            print(threading.current_thread().name, i)
            con.notify()  # 通知打印完成
            con.wait()  # 等待


con = threading.Condition()
threading.Thread(target=go1).start()
threading.Thread(target=go2).start()

Thread-1 0
Thread-2 1
Thread-1 2
Thread-2 3
Thread-1 4
Thread-2 5
Thread-1 6
Thread-2 7
Thread-1 8
Thread-2 9