ZCMU暑期训练四-B - Tokitsukaze and Mahjong

本文介绍了一个基于日本麻将的游戏算法,玩家需通过获取特定组合赢得游戏。文章详细解释了游戏规则,并提供了一段C++代码实现,用以计算玩家赢得游戏所需的最少额外手牌数。

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Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 11 to 99). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, ……, 9m, 1p, 2p, ……, 9p, 1s, 2s, ……, 9s.

In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.

Do you know the minimum number of extra suited tiles she needs to draw so that she can win?

Here are some useful definitions in this game:

A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:

[2m, 3p, 2s, 4m, 1s, 2s, 4s] — it contains no koutsu or shuntsu, so it includes no mentsu;
[4s, 3m, 3p, 4s, 5p, 4s, 5p] — it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
[5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] — it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.

Input
The only line contains three strings — the tiles in Tokitsukaze’s hand. For each string, the first character is a digit ranged from 11 to 99 and the second character is m, p or s.

Output
Print a single integer — the minimum number of extra suited tiles she needs to draw.

Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.

In the second example, Tokitsukaze already has a koutsu.

In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile — 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p].

题面:
两种胡牌方式
1,顺子 2,同样三张
前提是同花色;
问你还需要几张才能胡牌;
思路:全模拟

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstring>
using namespace std;
const int maxn=5;
int main()
{
  int ans=0;
  char a[maxn],b[maxn],c[maxn];
  cin>>a>>b>>c;
  if(strcmp(a,b)==0&&strcmp(a,c)==0)
  {
    ans=0;
  }
  else if(a[1]==b[1]&&a[1]==c[1])
  {
    if((a[0]==b[0]-1&&a[0]==c[0]-2)||(a[0]==b[0]-2&&a[0]==c[0]-1)
    ||(a[0]==b[0]+1&&a[0]==c[0]-1)||(a[0]==b[0]-1&&a[0]==c[0]+1)
    ||(a[0]==b[0]+1&&a[0]==c[0]+2)||(a[0]==b[0]+2&&a[0]==c[0]+1))
    {
      ans=0;
    }
    else if(a[0]==b[0]+1||a[0]==b[0]-1||a[0]==b[0]-2||a[0]==b[0]+2||
    a[0]==c[0]+1||a[0]==c[0]-1||a[0]==c[0]-2||a[0]==c[0]+2||
    b[0]==c[0]+1||b[0]==c[0]-1||b[0]==c[0]-2||b[0]==c[0]+2||
    a[0]==b[0]||a[0]==c[0]||b[0]==c[0])
    {
      ans=1;
    }
    else
    {
      ans=2;
    }
  }
  else
  {
    if((strcmp(a,b)==0)||(strcmp(a,c)==0)||(strcmp(b,c)==0))
    {
      ans=1;
    }
    else if((a[0]==b[0]+1&&a[1]==b[1])||(a[0]==c[0]+1&&a[1]==c[1])
    ||(a[0]==b[0]-1&&a[1]==b[1])||(a[0]==c[0]-1&&a[1]==c[1])||
    (a[0]==b[0]-2&&a[1]==b[1])||(a[0]==c[0]-2&&a[1]==c[1])||
    (a[0]==b[0]+2&&a[1]==b[1])||(a[0]==c[0]+2&&a[1]==c[1])||
    (b[0]==c[0]-1&&b[1]==c[1])||(b[0]==c[0]+1&&b[1]==c[1])||
    (b[0]==c[0]-2&&b[1]==c[1])||(b[0]==c[0]+2&&b[1]==c[1]))
    {
      ans=1;
    }
    else
    {
      ans=2;
    }
  }
  cout<<ans<<endl;
  return 0;
}
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