public class Try {
public static void main(String[]args){
int [][] a = {{1,2,3},{4,5,6},{7,8,9}};
int i,j,s = 0;
for ( i=0;i<3;i++){
System.out.println("===i的值=== "+i);
for ( j=0;j<i+1;j++){
System.out.println("---j的值--- "+j);
s = s+a[2-i][2-j];
System.out.println("此时的i为 "+i);
System.out.println("此时的j为 "+j);
System.out.println("输出a[2-i][2-j] = "+a[2-i][2-j]);
System.out.println("*****输出 "+s);
}
}
System.out.println("输出s的值 "+s);
}
}
for循环的分析
最新推荐文章于 2025-04-24 17:46:29 发布