http://codeforces.com/group/NVaJtLaLjS/contest/238204/problem/A
A. Taming the Herd
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output
Early in the morning, Farmer John woke up to the sound of splintering wood. It was the cows, and they were breaking out of the barn again!
Farmer John was sick and tired of the cows' morning breakouts, and he decided enough was enough: it was time to get tough. He nailed to the barn wall a counter tracking the number of days since the last breakout. So if a breakout occurred in the morning, the counter would be 00that day; if the most recent breakout was 33 days ago, the counter would read 33. Farmer John meticulously logged the counter every day.
The end of the year has come, and Farmer John is ready to do some accounting. The cows will pay, he says! But lo and behold, some entries of his log are missing!
Farmer John is confident that the he started his log on the day of a breakout. Please help him determine, out of all sequences of events consistent with the log entries that remain, the minimum and maximum number of breakouts that may have take place over the course of the logged time.
Input
The first line contains a single integer NN (1≤N≤1001≤N≤100), denoting the number of days since Farmer John started logging the cow breakout counter.
The second line contains NN space-separated integers. The iith integer is either −1−1, indicating that the log entry for day ii is missing, or a non-negative integer aiai (at most 100100), indicating that on day ii the counter was at aiai.
Output
If there is no sequence of events consistent with Farmer John's partial log and his knowledge that the cows definitely broke out of the barn on the morning of day 11, output a single integer −1−1. Otherwise, output two space-separated integers mm followed by MM, where mm is the minimum number of breakouts of any consistent sequence of events, and MM is the maximum.
Example
input
Copy
4 -1 -1 -1 1
output
Copy
2 3
Note
In this example, we can deduce that a breakout had to occur on day 3. Knowing that a breakout also occurred on day 1, the only remaining bit of uncertainty is whether a breakout occurred on day 2. Hence, there were between 2 and 3 breakouts in total.
题目分析:
读错题导致一直WA。没有理解什么情况输出-1,若给出数据中出现矛盾输出-1.我以为是全为-1时,输出-1.英语水平要待提高。
题读对后,题目不难。
代码:
#include<bits/stdc++.h>
#define INF 0x3f3f3f3f
using namespace std;
const int N=1000;
int a[N],b[N],vis[N];int n;
int main()
{
cin>>n;int flag=0;
for(int i=1;i<=n;i++)cin>>a[i];
memset(b,-1,sizeof(b));
for(int i=0;i<=n;i++)vis[i]=1;
for(int i=2;i<=n;i++)
{
if(a[i]>-1){
if(b[i-a[i]]==0)flag=1;else b[i-a[i]]=1;
for(int j=i-a[i]+1;j<=i;j++){
if(b[j]==1)flag=1;
else b[j]=0;
}
}
}
b[1]=1;int c1=0,c2=0;
for(int i=1;i<=n;i++){
if(b[i]==1)c1++;
if(b[i]==-1)c2++;
}
if(flag)puts("-1");
else printf("%d %d\n",c1,c1+c2);
}