1039 Course List for Student

最新推荐文章于 2024-12-02 11:52:39 发布

四郎别认输

最新推荐文章于 2024-12-02 11:52:39 发布

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分类专栏：算法文章标签： c++ 算法

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本文介绍了一个处理大量学生和课程注册信息的系统。该系统接收学生查询，返回每个学生已注册的课程列表。输入包括学生人数、课程总数及各课程的学生名单，输出为按查询顺序列出每个学生的课程注册详情。示例展示了系统的输入和输出格式，并提供了一个C++实现，该实现使用映射数据结构来存储和检索信息。

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Zhejiang University has 40000 students and provides 2500 courses. Now given the student name lists of all the courses, you are supposed to output the registered course list for each student who comes for a query.

Input Specification:

Each input file contains one test case. For each case, the first line contains 2 positive integers: N (≤40,000), the number of students who look for their course lists, and K (≤2,500), the total number of courses. Then the student name lists are given for the courses (numbered from 1 to K) in the following format: for each course i, first the course index i and the number of registered students Ni (≤200) are given in a line. Then in the next line, Ni student names are given. A student name consists of 3 capital English letters plus a one-digit number. Finally the last line contains the N names of students who come for a query. All the names and numbers in a line are separated by a space.

Output Specification:

For each test case, print your results in N lines. Each line corresponds to one student, in the following format: first print the student's name, then the total number of registered courses of that student, and finally the indices of the courses in increasing order. The query results must be printed in the same order as input. All the data in a line must be separated by a space, with no extra space at the end of the line.

Sample Input:

11 5
4 7
BOB5 DON2 FRA8 JAY9 KAT3 LOR6 ZOE1
1 4
ANN0 BOB5 JAY9 LOR6
2 7
ANN0 BOB5 FRA8 JAY9 JOE4 KAT3 LOR6
3 1
BOB5
5 9
AMY7 ANN0 BOB5 DON2 FRA8 JAY9 KAT3 LOR6 ZOE1
ZOE1 ANN0 BOB5 JOE4 JAY9 FRA8 DON2 AMY7 KAT3 LOR6 NON9

Sample Output:

ZOE1 2 4 5
ANN0 3 1 2 5
BOB5 5 1 2 3 4 5
JOE4 1 2
JAY9 4 1 2 4 5
FRA8 3 2 4 5
DON2 2 4 5
AMY7 1 5
KAT3 3 2 4 5
LOR6 4 1 2 4 5
NON9 0

#include <iostream>
#include <vector>
#include <math.h>
#include <algorithm>
#include <map>
#include <sstream>
#include <string.h>

using namespace std;

typedef long long ll;

map<int,vector<string>> courses;
vector<string> names;
map<string,vector<int>>cn;


int num[11];
int main()
{
    int k,n;
    cin>>n>>k;
    for(int i=0; i<k; i++)
    {
        int q,m;
        cin>>q>>m;
        for(int j=0; j<m; j++)
        {
            string name;
            cin>>name;
            cn[name].push_back(q);
        }
    }
    for(int i=0; i<n; i++)
    {
        string name;
        cin>>name;
        names.push_back(name);
    }

    for(int i=0; i<n; i++)
    {
        cout<<names[i];
        cout<<' '<<cn[names[i]].size();
        sort(cn[names[i]].begin(),cn[names[i]].end());
        for(int j=0; j<cn[names[i]].size(); j++)
        {
            cout<<' '<<cn[names[i]][j];
        }
        cout<<endl;
    }
}