Python计算、统计节假日剩余天数

原创已于 2022-09-23 11:00:30 修改 · 725 阅读

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于 2022-09-22 12:41:00 首次发布

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本文介绍了一个Python脚本，用于计算当前日期距离特定节假日的天数，包括周末、元旦、春节等，并展示了如何获取当前日期的星期信息。通过解析日期并使用农历库来准确计算农历节日的距离。

import datetime as dt
from zhdate import ZhDate #*注：农历库记得引入


def get_week_day(date):
    week_day_dict = {
        0: '星期一',
        1: '星期二',
        2: '星期三',
        3: '星期四',
        4: '星期五',
        5: '星期六',
        6: '星期天',
    }
    day = date.weekday()
    return week_day_dict[day]

def time_parse(today):
   distance_year = (dt.datetime.strptime(str(today.year) + "-01-01", "%Y-%m-%d") - today).days
   if distance_year < 0 :
          distance_year = (dt.datetime.strptime(str(today.year + 1) + "-01-01", "%Y-%m-%d") - today).days

   distance_big_year = (ZhDate(today.year, 1, 1).to_datetime() - today).days
   if distance_big_year < 0 :
        distance_big_year = (ZhDate((today.year + 1), 1, 1).to_datetime() - today).days

   distance_4_5 = (dt.datetime.strptime(str(today.year) + "-04-05", "%Y-%m-%d") - today).days
   if distance_4_5 < 0 :
        distance_4_5 = (dt.datetime.strptime(str(today.year + 1) + "-04-05", "%Y-%m-%d") - today).days

   distance_5_1 = (dt.datetime.strptime(str(today.year) + "-05-01", "%Y-%m-%d") - today).days
   if distance_5_1 < 0 :
        distance_5_1 = (dt.datetime.strptime(str(today.year + 1) + "-05-01", "%Y-%m-%d") - today).days

   distance_5_5 = (ZhDate(today.year, 5, 5).to_datetime() - today).days
   if distance_5_5 < 0 :
        distance_5_5 = (ZhDate(today.year + 1, 5, 5).to_datetime() - today).days

   distance_8_15 = (ZhDate(today.year, 8, 15).to_datetime() - today).days
   if distance_8_15 < 0 :
        distance_8_15 = (ZhDate(today.year + 1, 8, 15).to_datetime() - today).days

   distance_10_1 = (dt.datetime.strptime(str(today.year) + "-10-01", "%Y-%m-%d") - today).days
   if distance_10_1 < 0 :
        distance_10_1 = (dt.datetime.strptime(str(today.year + 1) + "-10-01", "%Y-%m-%d") - today).days

    # print("距离周末: ", 5 - today.weekday())
    # print("距离元旦: ", distance_year)
    # print("距离大年: ", distance_big_year)
    # print("距离清明: ", distance_4_5)
    # print("距离劳动: ", distance_5_1)
    # print("距离端午: ", distance_5_5)
    # print("距离中秋: ", distance_8_15)
    # print("距离国庆: ", distance_10_1)

   time_ = [
      {"v_": 5 - 1 - today.weekday(), "title": "周末"}, # 距离周末
        {"v_": distance_year, "title": "元旦"}, # 距离元旦
        {"v_": distance_big_year, "title": "过年"}, # 距离过年
        {"v_": distance_4_5, "title": "清明节"}, # 距离清明
        {"v_": distance_5_1, "title": "劳动节"}, # 距离劳动
        {"v_": distance_5_5, "title": "端午节"}, # 距离端午
        {"v_": distance_8_15, "title": "中秋节"}, # 距离中秋
        {"v_": distance_10_1, "title": "国庆节"}, # 距离国庆
   ]


   time_ = sorted(time_, key = lambda x: x['v_'], reverse = False)

   return time_


holiday = ''
today = dt.datetime.today()
time_ = time_parse(today)
for t_ in time_:
   if t_.get("v_") >= 0:
      holiday += '距离{}还有:{}天\n'.format(t_.get("title"), t_.get("v_"))


date_new = '{}年{}月{}日 {}'.format(today.year, today.month, today.day, get_week_day(today))


print(date_new)
print(holiday)