石头剪刀布小游戏

最新推荐文章于 2024-02-21 19:33:38 发布

@zhangzhengyang

最新推荐文章于 2024-02-21 19:33:38 发布

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文章标签： eclipse

本文链接：https://blog.youkuaiyun.com/qq_42766680/article/details/118735895

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这是一个简单的Java程序，玩家可以与电脑进行石头、剪刀、布游戏。程序通过Scanner获取用户输入，并使用Random类生成电脑的选择。根据双方选择判断胜负并输出结果。

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石头剪刀布小游戏

问题描述：玩家与电脑的小游戏。

import java.util.Random;
import java.util.Scanner;
public class GuessGame {
public static void main(String[] args) {
	int player;
    //用数组下标表示三个手势
	String[] arr = {"石头","剪刀","布"};
	Scanner sr = new Scanner(System.in);
	System.out.print("请输入：");
	player = sr.nextInt();
	while(true) {
	if(player>3 || player <=0) {
		System.out.println("输入的数字不对，请重新输入：");
		player = sr.nextInt();
	}
	else break;
	}
	//1表示石头，2表示剪刀，3表示布   
	Random rd = new Random();
	//随机生成一个1-3的数
	int computerSave = (int)(Math.random()*3+1);
	System.out.println("电脑出的是："+arr[computerSave-1]+"("+computerSave+")");
	System.out.println("玩家出的是："+arr[player-1]+"("+player+")");
	//电脑获胜的三种情况
	if((computerSave == 1 && player == 2) || (computerSave == 2 && player == 3) || (computerSave == 3 && player == 1)) {
		System.out.println("恭喜电脑获胜！");
	}
	//玩家获胜的三种情况
	if((computerSave == 1 && player == 3) || (computerSave == 2 && player == 1) || (computerSave == 3 && player == 2)) {
		System.out.println("恭喜玩家获胜！");
	}
	//平手的三种情况
	if((computerSave == 1 && player == 1) || (computerSave == 2 && player == 2) || (computerSave == 3 && player == 3)) {
		System.out.println("平手！");
	}
	}
	}