调试：抛出异常

Wenwen_IT

于 2022-11-14 15:37:21 发布

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文章标签： python

本文链接：https://blog.youkuaiyun.com/qq_42766312/article/details/127848749

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异常处理函数参数检查矩形框打印

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# 抛出异常

def boxPrint(symbol, width, height):
    if len(symbol) != 1:
        raise Exception('Symbol must be a single character string.')
    if width <= 2:
        raise Exception('Width must be greater than 2.')
    if height <=2:
        raise Exception('Height must be greater than 2.')
    print(symbol * width)
    for i in range(height - 2):
        print(symbol + (' ' * (width - 2)) + symbol)
    print(symbol * width)

for sym, w, h in (('*', 4, 4),('0', 20, 5),('x', 1, 3),('ZZ', 3, 3)):
    try:
        boxPrint(sym, w, h)
    except Exception as error:
        print('An exception happened: ' + str(error))