1001 A+B Format （20 分）

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于 2018-10-30 20:55:04 发布

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本文链接：https://blog.youkuaiyun.com/qq_42623428/article/details/83548713

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本文介绍了一种求和算法的实现，该算法接收两个整数作为输入，并以标准格式输出其和，其中数字每三位用逗号分隔。文章详细展示了如何处理不同范围内的整数，包括负数的正确格式化。

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Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

#include <bits/stdc++.h>
using namespace std;

int main()
{
    int a,b,c;
    cin>>a>>b;
    c=a+b;
    if(c<0)cout<<"-";
    c=abs(c);
    if(c<1000)cout<<c;
    else if(c<1000000){
        printf("%d,%03d",c/1000,c%1000);
    }
    else  {
        printf("%d,%03d,%03d",c/1000000,c/1000%1000,c%1000);
    }
}