Java发送get请求

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于 2022-11-24 14:11:31 发布

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分类专栏： java 文章标签： java json 前端

本文链接：https://blog.youkuaiyun.com/qq_41992943/article/details/128017563

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该博客演示了如何使用HttpGet进行HTTP请求，并处理返回的响应。通过设置Content-Type为'application/x-www-form-urlencoded'，向指定URL发送带有参数的请求。在接收到响应后，读取并检查响应内容是否包含特定字符串。

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String requestPath = "http://测试地址?name="+参数;
            HttpGet httpGet = new HttpGet(requestPath);
            //httpClient实例化
            CloseableHttpClient httpClient = HttpClients.createDefault();
            // 显示结果
            BufferedReader reader = null;
            try {
            // 设置类型 "application/x-www-form-urlencoded" "application/json"
            httpGet.setHeader("Content-Type", "application/x-www-form-urlencoded");
            // 执行请求并获取返回
            HttpResponse response = httpClient.execute(httpGet);
            //        System.out.println("Response toString()" + response.toString());
            HttpEntity entity1 = response.getEntity();
            // 显示结果
            reader = new BufferedReader(new InputStreamReader(entity1.getContent(), "UTF-8"));
            String line = null;
            StringBuffer responseSB = new StringBuffer();
            while ((line = reader.readLine()) != null) {
                responseSB.append(line);
            }
            if (!(responseSB.indexOf("哈哈哈，返回了") > -1)){
                return false;
            }
            } catch (Exception  e) {
                throw new RuntimeException(e);
            }finally {
                try {
                    reader.close();
                    httpClient.close();
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }