/***************************递归求1~N的和************************/
public class FunctionTest{
public static void main(String[] args){
System.out.println(sum(100));
}
public static int sum(int n){
int result;
if(n==1) return 1;
return n + sum(n-1);
}
}
/***************************递归求N的阶乘************************/
public class FunctionTest{
public static void main(String[] args){
System.out.println(factorial(9));
}
public static int factorial(int n){
if(n==0) return 1;
return n*factorial(n-1);
}
}