PAT 1065 A+B and C (64bit)

最新推荐文章于 2024-07-30 05:19:25 发布

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最新推荐文章于 2024-07-30 05:19:25 发布

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分类专栏：刷题题解文章标签： PAT A+B and C (64bit) 1-65

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本文探讨了在给定三个64位整数A、B和C的情况下，如何判断A+B是否大于C的问题，特别关注溢出处理。通过分析输入规格、输出规格及示例输入输出，提出了一种有效的解决方案，避免了直接相加可能导致的溢出错误。

题目
1065 A+B and C (64bit) (20 分)
Given three integers A, B and C in [−2
63
,2
63
], you are supposed to tell whether A+B>C.

Input Specification:
The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:
For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).

Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false

题目意思
判断a+b是否大于c

注意溢出问题

代码

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<cmath>
#include<map>

using namespace std;

int main()
{
    int n;
    scanf("%d",&n);
    int flag=1;
    while(n--)
    {
        long long a,b,c,hx;
        scanf("%lld%lld%lld",&a,&b,&c);
        printf("Case #%d: ",flag++);
        hx=a+b;
        if(a>0&&b>0&&hx<=0)
            printf("true\n");
        else if(a<0&&b<0&&hx>=0)
            printf("false\n");
        else if(hx>c)
            printf("true\n");
        else
            printf("false\n");
    }
    return 0;
}