题目
1050 String Subtraction (20 分)
Given two strings S1 and S2 , S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might not be that simple to do it fast.
Input Specification:
Each input file contains one test case. Each case consists of two lines which gives S1 and S2, respectively. The string lengths of both strings are no more than 104. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.
Output Specification:
For each test case, print S1−S2in one line.
Sample Input:
They are students.
aeiou
Sample Output:
Thy r stdnts.
题目意思
给两个字符串s1,s2,输出s1-s2
思路
直接模拟,需要注意的是字符串范围是10的4次方,其次是gets()函数,一开始用c++交,编译错误,想到可能是gets()的问题就改成c,就过了。
#include<stdio.h>
#include<string.h>
#include<math.h>
char hx[10003];
char a[100003];
int mz[1003]={0};
int main()
{
gets(hx);
gets(a);
for(int i=0;i<strlen(a);i++)
mz[a[i]]=1;
for(int i=0;i<strlen(hx);i++)
{
if(!mz[hx[i]])
{
printf("%c",hx[i]);
}
}
return 0;
}