hdu-6308（输出格式，时间转换）

最新推荐文章于 2024-07-24 09:30:00 发布

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最新推荐文章于 2024-07-24 09:30:00 发布

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分类专栏： aa题目题解

本文链接：https://blog.youkuaiyun.com/qq_41829060/article/details/81347692

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本文介绍了一种解决国际编程竞赛中遇到的时区问题的方法。通过输入北京时间（UTC+8），计算并输出其他指定时区的具体时间。文章还提供了一个示例代码，展示了如何进行时间转换。

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Time Zone

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2849 Accepted Submission(s): 902

Problem Description

Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone s.

Input

There are multiple test cases. The first line of input contains an integer T (1≤T≤106), indicating the number of test cases. For each test case:
The first line contains two integers a, b (0≤a≤23,0≤b≤59) and a string s in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤9).

Output

For each test, output the time in the format of hh:mm (24-hour clock).

Sample Input

3 11 11 UTC+8 11 12 UTC+9 11 23 UTC+0

Sample Output

11:11 12:12 03:23

Source

2018 Multi-University Training Contest 1

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心得：输入的格式要注意，按照题目中的来。

将第8时区时间化为分钟，求要到达的时区和第8时区之间的差值，再加上原来第八时区的时间

注意，‘+’还是‘-’，‘-’的话要最后变为正数。

#include<bits/stdc++.h>
using namespace std;
int main(void)
{
	int h,m,t;
	double d;
	char ch;
	int t1,t2,tp;
	while(~scanf("%d",&t))
	{
		while(t--)
		{
			scanf("%d %d UTC%c%lf",&h,&m,&ch,&d);
			t1=h*60+m;
			tp=(int)(d*10);
			if(ch=='+')
			{
				t2=t1+tp*6-8*60;
			}
			else if(ch=='-')
			{
				t2=t1-tp*6-8*60;
			}
			t2=t2%(24*60);
			if(t2<0) t2+=24*60;
			h=t2/60;
			m=t2%60;
			printf("%02d:%02d\n",h,m);
		}
	}
	return 0;
}