from collections import Iterable
d = {'a': 1, 'b': 2, 'c': 3}
for key in d:
print(key)
for value in d.values():
print(value)
for key, value in d.items(): #这是键值对的迭代方式
print(key, value)
c = ['123', '321', '456']
for i, num in enumerate(c): #list的迭代用内置函数
print(i, num)
# for i, num in c:
# print(i, num) #迭代的时候,list没有索引机制,只能访问的时候用索引访问
print(isinstance(c, Iterable))
for x, y in [(1, 1), (2, 4), (3, 9)]:
print(x, y)
请使用迭代查找一个list中最小和最大值,并返回一个tuple:
def findMinAndMax(L):
if len(L) == 0:
return None, None
min = L[0]
max = L[0]
for i in L:
if i < min:
min = i
if i > max:
max = i
return min, max
if findMinAndMax([]) != (None, None):
print('测试失败!')
elif findMinAndMax([7]) != (7, 7):
print('测试失败!')
elif findMinAndMax([7, 1]) != (1, 7):
print('测试失败!')
elif findMinAndMax([7, 1, 3, 9, 5]) != (1, 9):
print('测试失败!')
else:
print('测试成功!')
Python课后练习:迭代
最新推荐文章于 2022-03-30 14:27:04 发布