1005. Spell It Right (20)（C++)

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本文介绍了一个C++程序，该程序接收一个非负整数作为输入，并计算其各位数字之和，然后将这个和的每一位数字以英文形式输出。示例中使用了12345作为输入，程序会输出“onefive”。文章主要关注数字串与字符串间的转换，并介绍了如何利用to_string()函数实现这一转换。

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Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10100).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

Sample Output:one five

知识点：主要是数字串和字符串之间的转换；重点关注to_string（）的用法；

#include <iostream>
#include <string>
using namespace std;
string chinese[10]={"zero","one","two","three","four","five","six","seven","eight","nine"};
int main(){
	int num = 0;
	string s, ans;
	cin>>s;
	for(int i = 0; i < s.length(); ++ i)
		num += s[i] - '0';
	ans = to_string(num);
	printf("%s",chinese[ans[0] - '0'].c_str());
	for(int i = 1; i < ans.length(); ++ i)
		printf(" %s",chinese[ans[i] - '0'].c_str());
}