A - A water problem HDU - 5832

宇宙两行星周期计算
本文介绍了一段代码,用于计算两个虚构宇宙中的行星Haha和Xixi在宇宙诞生后的第N天是否各自处于其年份的第一天。通过输入特定的大整数N,程序能够高效判断并输出结果。

Two planets named Haha and Xixi in the universe and they were created with the universe beginning. 

There is 7373 days in Xixi a year and 137137 days in Haha a year. 

Now you know the days NN after Big Bang, you need to answer whether it is the first day in a year about the two planets.

Input

There are several test cases(about 55 huge test cases). 

For each test, we have a line with an only integer N(0≤N)N(0≤N), the length of NN is up to 1000000010000000.

Output

For the i-th test case, output Case #i: , then output "YES" or "NO" for the answer.

Sample Input

10001
0
333

Sample Output

Case #1: YES
Case #2: YES
Case #3: NO
#include <iostream>
#include<stdio.h>
#include<algorithm>
#include<string.h>
using namespace std;
char s[10000010];
int st(char s[],int a)
{
    int n=0,i;
    int len=strlen(s);
    n=s[0]-'0';
    for(i=1; i<len; i++)
    {
        n*=10;
        n+=s[i]-'0';
        if(n>=10001)
            n=n%10001;
    }
    if(n==0)return 1;
    else return 0;
}
int main()
{int p=0;
    while(scanf("%s",s)!=EOF)
    {p++;
        int a=10001;
        int k=st(s,a);
        if(k)printf("Case #%d: YES\n",p);
        else printf("Case #%d: NO\n",p);
    }
    return 0;
}

 

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值