1.T160 相交链表
相交链表
/**
* @BelongsProject: study
* @BelongsPackage: PACKAGE_NAME
* @Author: Alone
* @Description:
*/
public class T160 {
/**
* 双指针
* 最后是空等于空
* @param headA
* @param headB
* @return
*/
public ListNode getIntersectionNode(ListNode headA, ListNode headB) {
ListNode pa = headA, pb = headB;
while(pa != pb){
pa = pa != null ? pa.next : headB;
pb = pb != null ? pb.next : headA;
}
return pa;
}
}
2.T206 反转链表
反转链表
/**
* @BelongsProject: study
* @BelongsPackage: PACKAGE_NAME
* @Author: Alone
* @CreateTime: 2021-03-22 16:56
* @Description:
*/
public class T206 {
public ListNode reverseList(ListNode head) {
ListNode pre = null;
ListNode now = head;
ListNode next = null;
while (now != null) {
next = now.next;
now.next = pre;
pre = now;
now = next;
}
return pre;
}
}
3.T21 合并两个有序链表
合并两个有序链表
/**
* @BelongsProject: study
* @BelongsPackage: PACKAGE_NAME
* @Author: Alone
* @CreateTime: 2021-03-21 21:31
* @Description:
*/
public class T21 {
/**
* 非递归
* @param l1
* @param l2
* @return
*/
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if(l1 == null)
return l2;
if(l2 == null)
return l1;
if(l1.val <= l2.val){
l1.next = mergeTwoLists(l1.next, l2);
return l1;
} else {
l2.next = mergeTwoLists(l1, l2.next);
return l2;
}
}
}
4.T83 删除排序链表中的重复元素
删除排序链表中的重复元素
/**
* @BelongsProject: study
* @BelongsPackage: PACKAGE_NAME
* @Author: Alone
* @CreateTime: 2021-03-22 17:01
* @Description:
*/
public class T83 {
public ListNode deleteDuplicates(ListNode head) {
if(head == null)
return head;
ListNode now = head;
ListNode next = head.next;
while (now != null && next != null){
if(now.val == next.val){
if(next.next != null){
next = next.next;
now.next = next;
} else {
now.next = null;
break;
}
} else {
if(next.next != null){
now = next;
next = next.next;
} else {
break;
}
}
}
return head;
}
}
5.T19 删除链表的倒数第 N 个结点
删除链表的倒数第 N 个结点
/**
* @BelongsProject: study
* @BelongsPackage: PACKAGE_NAME
* @Author: Alone
* @CreateTime: 2021-03-22 17:14
* @Description:
*/
public class T19 {
public ListNode removeNthFromEnd(ListNode head, int n) {
ListNode fast = head;
ListNode slow = head;
for (int i = 0; i < n; i++) {
fast = fast.next;
}
if(fast.next == null){
//链表已经走到头了
return head.next;
}
while (fast.next != null){
fast = fast.next;
slow = slow.next;
}
//slow的下一个是要删掉的节点
slow.next = slow.next.next;
return head;
}
}
6.T24 两两交换链表中的节点
两两交换链表中的节点
/**
* @BelongsProject: study
* @BelongsPackage: PACKAGE_NAME
* @Author: Alone
* @CreateTime: 2021-03-23 19:32
* @Description:
*/
public class T24 {
public ListNode swapPairs(ListNode head) {
ListNode res = new ListNode(0);
res.next = head;
ListNode front = res, tmp = res.next;
while (tmp != null && tmp.next != null){
ListNode next = tmp.next;
ListNode behind = next.next;
front.next = next;
tmp.next = behind;
next.next = tmp;
front = tmp;
tmp = behind;
}
return res.next;
}
}
7.T445 两数相加 II
两数相加 II
import java.util.Stack;
/**
* @BelongsProject: study
* @BelongsPackage: PACKAGE_NAME
* @Author: Alone
* @CreateTime: 2021-03-23 19:47
* @Description:
*/
public class T445 {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
Stack<ListNode> s1 = new Stack<>();
Stack<ListNode> s2 = new Stack<>();
ListNode tmp1 = l1, tmp2 = l2;
while (tmp1 != null){
s1.push(tmp1);
tmp1 = tmp1.next;
}
while (tmp2 != null){
s2.push(tmp2);
tmp2 = tmp2.next;
}
ListNode res = new ListNode(-1), p1 = null, p2 = null;
int digit = 0, now = 0;
while (!s1.empty() || !s2.empty()){
p1 = null;
p2 = null;
if(!s1.empty())
p1 = s1.pop();
if(!s2.empty())
p2 = s2.pop();
now = 0;
if(p1 != null)
now += p1.val;
if(p2 != null)
now += p2.val;
now += digit;
digit = now / 10;
if(res.next == null)
res.next = new ListNode(now % 10);
else {
ListNode next = res.next;
res.next = new ListNode(now % 10);
res.next.next = next;
}
}
if(digit != 0){
ListNode next = res.next;
res.next = new ListNode(digit);
res.next.next = next;
}
return res.next;
}
public static void main(String[] args) {
ListNode l1 = new ListNode(7);
l1.next = new ListNode(2);
l1.next.next = new ListNode(4);
l1.next.next.next = new ListNode(3);
ListNode l2 = new ListNode(5);
l2.next = new ListNode(6);
l2.next.next = new ListNode(4);
T445 t445 = new T445();
ListNode node = t445.addTwoNumbers(l1, l2);
while (node != null){
System.out.println(node.val);
node = node.next;
}
}
}
8.T234 回文链表
回文链表
/**
* @BelongsProject: study
* @BelongsPackage: PACKAGE_NAME
* @Author: Alone
* @CreateTime: 2021-03-24 13:31
* @Description:
*/
public class T234 {
public boolean isPalindrome(ListNode head) {
//找到链表中点
ListNode slow = head;
ListNode fast = head;
while (fast.next != null && fast.next.next != null){
slow = slow.next;
fast = fast.next.next;
}
//切割链表
ListNode behind = slow.next;
slow.next = null;
//反转后半部分链表
ListNode pre = null, now = behind, next = null;
while (now != null){
next = now.next;
now.next = pre;
pre = now;
now = next;
}
//比较两部分是否相等
ListNode p1 = head, p2 = pre;
while (p2 != null){
if(p1.val != p2.val)
return false;
p1 = p1.next;
p2 = p2.next;
}
return true;
}
public static void main(String[] args) {
ListNode node = new ListNode(1);
node.next = new ListNode(2);
T234 t234 = new T234();
System.out.println(t234.isPalindrome(node));
}
}
9.T725 分隔链表
分隔链表
/**
* @BelongsProject: study
* @BelongsPackage: PACKAGE_NAME
* @Author: Alone
* @CreateTime: 2021-03-24 14:13
* @Description:
*/
public class T725 {
public ListNode[] splitListToParts(ListNode root, int k) {
//统计链表总长度
ListNode cur = root;
int len = 0;
while (cur != null){
cur = cur.next;
len ++;
}
//计算每段的长度
int num = len / k;
int front = len % k;
//分割链表
ListNode[] res = new ListNode[k];
ListNode tmp = root;
for (int i = 0; i < k && tmp != null; i++) {
res[i] = tmp;
int size = num + (front-- > 0 ? 1 : 0);
for (int j = 0; j < size - 1; j++) {
tmp = tmp.next;
}
ListNode next = tmp.next;
tmp.next = null;
tmp = next;
}
return res;
}
public static void main(String[] args) {
ListNode node = new ListNode(1);
node.next = new ListNode(2);
node.next.next = new ListNode(3);
node.next.next.next = new ListNode(4);
T725 t725 = new T725();
ListNode[] nodes = t725.splitListToParts(node, 5);
}
}
10.T328 奇偶链表
奇偶链表
import java.util.List;
/**
* @BelongsProject: study
* @BelongsPackage: PACKAGE_NAME
* @Author: Alone
* @CreateTime: 2021-03-07 10:32
* @Description:
*/
public class T328 {
public ListNode oddEvenList(ListNode head) {
if(head == null)
return null;
ListNode odd = new ListNode(-1);
ListNode oddTail = odd;
ListNode even = new ListNode(-1);
ListNode evenTail = even;
boolean flag = true;
while (head != null){
if(flag){
oddTail.next = head;
oddTail = oddTail.next;
} else {
evenTail.next = head;
evenTail = evenTail.next;
}
flag = !flag;
head = head.next;
}
oddTail.next = even.next;
evenTail.next = null;//不加这行可能会出现循环
return odd.next;
}
}
题目来源
https://github.com/CyC2018/CS-Notes/blob/master/notes/Leetcode%20%E9%A2%98%E8%A7%A3%20-%20%E9%93%BE%E8%A1%A8.md