直接放例题吧:在
母函数
#include <iostream>
#include<algorithm>
#include<cstdlib>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<deque>
#include<queue>
#include<vector>
#include<stack>
#include <climits>
#include<ctime>
using namespace std;
#define eps 1e-10
#define pi acos(-1)
#define e exp(1)
#define INF 0x3f3f3f3f
typedef long long LL;
LL a[1100],b[1100];
int main()
{
int n;
while(cin>>n&&n)
{
for(int i = 0; i <= n; i++)
{
a[i] = 1;
b[i] = 0;
}
for(int i = 2; i * i <= n; i++)
{
int t = i * i;
for(int j = 0; j <= n; j++)
{
for(int k = 0; k + j <= n; k += t)
{
b[k + j] += a[j];
}
}
for(int j = 0; j <= n; j++)
{
a[j] = b[j];
b[j] = 0;
}
}
cout<<a[n]<<endl;
}
return 0;
}
斯特林数
#include <iostream>
#include<algorithm>
#include<cstdlib>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<deque>
#include<queue>
#include<vector>
#include<stack>
#include <climits>
#include<ctime>
using namespace std;
#define eps 1e-10
#define pi acos(-1)
#define e exp(1)
#define INF 0x3f3f3f3f
typedef long long LL;
int main()
{
int T;
cin>>T;
while(T--)
{
int n;
cin>>n;
if(n<10)
{
double ans=1;
for(int i=1;i<=n;i++)
ans+=log10(i);
cout<<(LL)ans<<endl;
}
else
{
double ans=log10(sqrt(2*pi*n))+n*log10(n/e)+1;
cout<<(LL)ans<<endl;
}
}
}
卡特兰数:
卡特兰数比较大最好用Java大数写
import java.util.*;
import java.math.*;
public class Main {
public static void main(String args[]) {
BigInteger []res = new BigInteger[104];
res[0] = new BigInteger("1");
res[1] = new BigInteger("1");
for(int i = 2;i<=100;i++)
{
res[i] = res[i - 1].multiply(BigInteger.valueOf(4 * i - 2)).divide(BigInteger.valueOf(i+1));
}
int n ;
Scanner cin = new Scanner(System.in);
while(cin.hasNext())
{
n = cin.nextInt();
System.out.println(res[n]);
}
}
}