【题解】UVA 1585

目录

 

题目描述

题意分析

AC代码

---

题目描述

There is an objective test result such as “OOXXOXXOOO”. An ‘O’ means a correct answer of a problem and an ‘X’ means a wrong answer. The score of each problem of this test is calculated by itself and its just previous consecutive ‘O’s only when the answer is correct. For example, the score of the 10th problem is 3 that is obtained by itself and its two previous consecutive ‘O’s. Therefore, the score of “OOXXOXXOOO” is 10 which is calculated by “1+2+0+0+1+0+0+1+2+3”. You are to write a program calculating the scores of test results.

Input

Your program is to read from standard input. The input consists of T test cases. The number of test cases T is given in the first line of the input. Each test case starts with a line containing a string composed by ‘O’ and ‘X’ and the length of the string is more than 0 and less than 80. There is no spaces between ‘O’ and ‘X’.

Output

Your program is to write to standard output. Print exactly one line for each test case. The line is to contain the score of the test case.

 

Sample Input

5

OOXXOXXOOO

OOXXOOXXOO

OXOXOXOXOXOXOX

OOOOOOOOOO

OOOOXOOOOXOOOOX

 

Sample Output

10

9

7

55

30

题意分析

题意： 遇到 X 就停止连击，否则则加上连击分数（例如：连续的OO 则是 1 + 2）。问给你这个串的分数结果是多少。

AC代码

/**
* Copyright(c)
* All rights reserved.
* Author : Universal
* Description : sample
*/
#include <bits/stdc++.h>
#define MAXN 100005
#define INF 0x3f3f3f3f
#define PI acos(-1)
using namespace std;
typedef long long ll;

int main(){
    int t,sum,combe;
    string s;
    cin>>t;
    while(t--){
        cin>>s;
        sum = 0;combe =0;
        for(int i=0;i<s.size();i++){
            if(s[i] == 'O') {
                sum += (++combe);
            }
            else{
                combe = 0;
            }
        }
        cout<<sum<<endl;
    }
    return 0;
}