HDOJ 1720 A+B Coming

最新推荐文章于 2020-01-16 21:46:34 发布

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最新推荐文章于 2020-01-16 21:46:34 发布

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Problem Description

Many classmates said to me that A+B is must needs.
If you can’t AC this problem, you would invite me for night meal. ^_^

Input

Input may contain multiple test cases. Each case contains A and B in one line.
A, B are hexadecimal number.
Input terminates by EOF.

Output

Output A+B in decimal number in one line.

Sample Input

1 9 A B a b

Sample Output

10 21 21

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
char a[100];
char b[100];
int htod(char str[])
{
	int res=0;
	int j = 0;
	for (int i = strlen(str) - 1; i >= 0; i--)
	{
		if (str[i] >= '0'&&str[i] <= '9')
			res += (str[i] - '0')*pow(16, j++);
		else if (str[i] >= 'A'&&str[i] <= 'Z')
			res += (str[i] - 55)*pow(16, j++);
		else
			res += (str[i] - 87)*pow(16, j++);
	}
	return res;
}
int main()
{
	while (scanf("%s%s", a, b) != EOF)
	{
		printf("%d\n", htod(a) + htod(b));
	}
	return 0;
}