select trunc( to_date('2005-12','yyyy-mm'),'yyyy') first_day , last_day(add_months(trunc(to_date('2005-12','yyyy-mm'),'y'),11))+ 1 - 1 / 86400 last_day FROM DUAL;
ORACLE:根据年月获取该年的第一天和最后一天
最新推荐文章于 2024-03-27 08:40:36 发布
select trunc( to_date('2005-12','yyyy-mm'),'yyyy') first_day , last_day(add_months(trunc(to_date('2005-12','yyyy-mm'),'y'),11))+ 1 - 1 / 86400 last_day FROM DUAL;