复制可以直接使用 代码没什么 可以讲解的这道题有非常多的实现方法
function getweather() {
//TODO:请补充代码
$.ajax({
type: "get",
dataType: "json",
url: "js/weather.json",
success: function (data) {
var day = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"] //各个 id
var datas = data.result // 获得结果集
var kid,grandson,g_son //孩儿们
for(var i = 1 ;i<=datas.length ;i++){
kid = $("#" + day[i-1]).children()
grandson = kid[1].children
g_son =grandson[3].children
kid[0].src=datas[i-1].weather_icon//天气图标
grandson[0].innerText = datas[i-1].wind//天气
grandson[1].innerText = datas[i-1].temperature//温度
grandson[2].innerText = datas[i-1].winp//风级
g_son[0].innerText = datas[i-1].days//日期
g_son[1].innerText = datas[i-1].week//星期几
}
}
})
}
getweather();