图片
putVal源码
final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
boolean evict) {
Node<K,V>[] tab; Node<K,V> p; int n, i;
//判断当前的数组是否已经进行了初始化
if ((tab = table) == null || (n = tab.length) == 0)
//没有初始化,初始化空间,或者扩容数组
n = (tab = resize()).length;
//tab:当前Node数组
//p = tab[i = (n - 1) & hash] index=(n-1) & hash
if ((p = tab[i = (n - 1) & hash]) == null)
tab[i] = newNode(hash, key, value, null);
//tab[2] = newNode(hash,"杨过", "小龙女", null);
//如果坑位已经被占
else {
Node<K,V> e; K k;
//判断当前元素Key是否已经存在
if (p.hash == hash &&
((k = p.key) == key || (key != null && key.equals(k))))
//如果key已经存在,替换旧值
e = p;
//判断是否是红黑树
else if (p instanceof TreeNode)
//如果是红黑树,那么向树中插入元素(为了树的平衡,有相应操作:左旋、右旋、着色)
e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
else {
//如果不是红黑树,那么就遍历当前的链表
for (int binCount = 0; ; ++binCount) {
if ((e = p.next) == null) {
p.next = newNode(hash, key, value, null);//创建节点加到链表尾部
//链表长度达到8或者大于8
if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
treeifyBin(tab, hash);//转为红黑树
break;
}
//判断是否有重复的元素
if (e.hash == hash &&
((k = e.key) == key || (key != null && key.equals(k))))
break;
p = e;
}
}
//替换旧值
if (e != null) { // existing mapping for key
V oldValue = e.value;
if (!onlyIfAbsent || oldValue == null)
e.value = value;
afterNodeAccess(e);
return oldValue;
}
}
//迭代器,failfast
++modCount;
//判断当前hashmap容量是否达到扩容的阈值
if (++size > threshold)
resize();//进行扩容
afterNodeInsertion(evict);
return null;
}