解题思路:详见https://blog.youkuaiyun.com/acm_cxq/article/details/51626668
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#define N 3008
#define ll long long
using namespace std;
int p[N],r[N],t;
double dp[3009];
ll n,m,ans[3009];
void prime()
{
t=0;
for(int i=2;i<N;i++)
{
if(!p[i])
{
r[t++]=i;
for(int j=i+i;j<N;j+=i)
p[j]=1;
}
}
}
void solve()
{
memset(dp,0,sizeof(dp));
double a;
for(int i=0;i<t;i++)
{
a=log(r[i]*1.0);
for(int j=n;j>=r[i];j--)
{
for(int k=r[i],q=1;k<=j;k*=r[i],q++)
{
if(dp[j-k]+q*a>dp[j])
{
dp[j]=dp[j-k]+q*a;
ans[j]=(ans[j-k]*k)%m;
}
}
}
}
printf("%lld\n",ans[n]);
}
int main()
{
prime();
//freopen("t.txt","r",stdin);
while(scanf("%d%d",&n,&m)!=EOF)
{
for(int i=0;i<=n;i++)
{
dp[i]=0;
ans[i]=1;
}
solve();
}
return 0;
}