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RSS订阅原创 Day4：Leetcode-92. Reverse Linked List
Sloution 1:# Definition for singly-linked list.# class ListNode:# def __init__(self, val=0, next=None):# self.val = val# self.next = nextclass Solution: def reverseBetween(self, head: ListNode, left: int, right: int) -.
2021-09-22 20:18:39
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原创 Day3：Leetcode-206. Reverse Linked List
In a linknode list，we define a = list()，then we add some nodes，if we write a[0].next = a[1]， that's fine ,it works, but when we turn to a[1].next = a[0]，it time exceed，which confused me a lot.But finally I solved it. because,if we say a[1].next = a[0]...
2021-09-20 20:21:00
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原创 Day2：Leetcode-83.Remove Duplicates from Sorted List
Solution 1：It is a sorted linked list, we can delete all duplicates one by one,but at first I made a mistake in case [0,0,0,0,0] , because I set pre number 0,therefore I turn it to be -99,that is okay.class Solution {public: ListNode* deleteDu.
2021-09-19 19:57:17
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原创 Day1：Leetcode-19.Remove Nth Node From End of List
Tips:There is something noteworthy in C++ code，function getlen(LinkList * head)，this formal parameteris fake，if we call thisfuntion，ouractual parameter head will not change。That is different from array，for instance int fun(int a[])，it will change our a...
2021-09-18 21:49:11
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