1001A+B Format

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本篇博客介绍了一道编程题目：计算两个整数a和b的和，并以标准格式输出结果，即每三位数字用逗号分隔。示例输入为-1000000和9，输出为-999,991。提供了C++和Java两种语言的代码实现。

1001. A+B Format (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

提交代码

#include <iostream>
#include <algorithm> 
#include <string>
using namespace std;
int main()
{
  string s;
  int a, b;
  cin >> a >> b;
  s = to_string(a + b);
  int len = s.length();
  for (int i = 0; i < len; i++) {
    cout << s[i];
    if (s[i] == '-') continue;
    if ((i + 1)  % 3 == len % 3 && i != len - 1) {
      cout << ",";
    }
  }
   return 0;
}

package PATBasic;

import java.util.Scanner;

public class  Test1001{
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int count = 0;  
		int n = sc.nextInt();
		sc.close();
		while (n > 1) {
			if (n % 2 == 1) { 
				n = 3 * n + 1;
			}
			n /= 2;
			count++;
		}
		System.out.println(count);
	}
}