杭电oj1197 c++

最新推荐文章于 2020-02-02 10:57:21 发布

结庐境

最新推荐文章于 2020-02-02 10:57:21 发布

阅读量372

点赞数

CC 4.0 BY-SA版权

分类专栏： OJ练习

本文链接：https://blog.youkuaiyun.com/qq_39587172/article/details/79302561

该博客介绍了一个编程问题，要求找到所有四位数的数字，其十进制、十六进制和十二进制表示的数字和相等。例如，2992是满足条件的第一个数字。博主给出了通过测试的简洁代码示例。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

题目简介：

Problem Description

Find and list all four-digit numbers in decimal notation that have the property that the sum of its four digits equals the sum of its digits when represented in hexadecimal (base 16) notation and also equals the sum of its digits when represented in duodecimal (base 12) notation.

For example, the number 2991 has the sum of (decimal) digits 2+9+9+1 = 21. Since 2991 = 1*1728 + 8*144 + 9*12 + 3, its duodecimal representation is 1893(12), and these digits also sum up to 21. But in hexadecimal 2991 is BAF16, and 11+10+15 = 36, so 2991 should be rejected by your program.

The next number (2992), however, has digits that sum to 22 in all three representations (including BB016), so 2992 should be on the listed output. (We don't want decimal numbers with fewer than four digits - excluding leading zeroes - so that 2992 is the first correct answer.)

Input

There is no input for