1061 Dating (20 分) bug 简单模拟

最新推荐文章于 2021-01-19 21:55:30 发布

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通过解析Sherlock收到的加密信息，利用特定的字符匹配规则，成功解码出周四14:04的约会时间。输入为四段不空字符串，输出为标准化的日期时间格式。

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Sherlock Holmes received a note with some strange strings: Let’s date! 3485djDkxh4hhGE 2984akDfkkkkggEdsb s&hgsfdk d&Hyscvnm. It took him only a minute to figure out that those strange strings are actually referring to the coded time Thursday 14:04 – since the first common capital English letter (case sensitive) shared by the first two strings is the 4th capital letter D, representing the 4th day in a week; the second common character is the 5th capital letter E, representing the 14th hour (hence the hours from 0 to 23 in a day are represented by the numbers from 0 to 9 and the capital letters from A to N, respectively); and the English letter shared by the last two strings is s at the 4th position, representing the 4th minute. Now given two pairs of strings, you are supposed to help Sherlock decode the dating time.

Input Specification:

Each input file contains one test case. Each case gives 4 non-empty strings of no more than 60 characters without white space in 4 lines.

Output Specification:

For each test case, print the decoded time in one line, in the format DAY HH:MM, where DAY is a 3-character abbreviation for the days in a week – that is, MON for Monday, TUE for Tuesday, WED for Wednesday, THU for Thursday, FRI for Friday, SAT for Saturday, and SUN for Sunday. It is guaranteed that the result is unique for each case.

Sample Input:

3485djDkxh4hhGE
2984akDfkkkkggEdsb
s&hgsfdk
d&Hyscvnm

Sample Output:

THU 14:04

Note

找第一次出现的东西找到一定要记得break掉，这么简单的问题查了好久。。。

Code

#include<cstdio>
#include<iostream>
#include<string>
#include<algorithm>
using namespace std;
string weeks[7] = {"MON ", "TUE ", "WED ", "THU ", "FRI ", "SAT ", "SUN "};
int main() {
  int cnt=0, i, j=4, k;
  int week, hour, minute;
  string a, b, c, d;
  cin >> a >> b >> c >> d;
  for(i = 0; i < a.size() && i < b.size();i++){
   if(a[i] >= 'A' && a[i] <= 'Z' && b[i] >= 'A' && b[i] <= 'Z' && a[i] == b[i]){
      if(cnt == 0 && a[i] <= 'G' && b[i] <= 'G')  { week=a[i] - 'A' ;  cnt++;}
      else if (cnt ==  1 && a[i] <= 'N' &&b[i] <= 'N'){
        hour = a[i] - 'A' + 10;

      }
    }
    else if(a[i] >= '0' && a[i] <= '9' && b[i] >= '0' && b[i] <= '9' && a[i] == b[i] && cnt==1) {
      hour=a[i] - '0';
    }
  }
  for(i = 0;i < c.size() && i < d.size();i++ ) {
    if(c[i] == d[i] && ((c[i] >= 'a' && c[i] <= 'z' && d[i] >= 'a' && d[i] <= 'z') || (c[i] >= 'A' && c[i] <= 'Z' && d[i] >= 'A' && d[i] <= 'Z')) ){
      minute = i;
      break;
    }
  } 
  cout << weeks[week] ;
  printf("%02d:%02d", hour, minute);
  return 0;
}