C/C++ | 27-19 写出程序把一个链表中的接点顺序倒排

#include <cstdio>
#include <deque>
#include <algorithm>
#include <iterator>
#include <stdio.h>  
#include <stdlib.h>
#include <iostream>
#include <string.h>
#include <assert.h>

using namespace std;

typedef struct LNode
{
	int data;
	struct LNode *next;
}LNode;

LNode *CreateLink(int num)  // 构造
{
	int i = 1;
	LNode *head, *tail, *p;
	head = (LNode *)malloc(sizeof(LNode));
	tail = head;
	while (num--)
	{
		p = (LNode *)malloc(sizeof(LNode));
		p->data = i;
		tail->next = p;
		tail = p;
		i++;
	}
	tail->next = NULL;
	return head;
}

LNode *FindLink(LNode *head, int X)  //查找
{
	assert(head != NULL);
	LNode *chick = head->next;
	while (chick != NULL)
	{
		if (chick->data == X)
			return chick;
		else
			chick = chick->next;
	}
	return NULL;
}

void DeleteLink(LNode *head, int X)  //删除
{
	assert(head != NULL);
	LNode *p;
	LNode *q;
	p = FindLink(head, X);
	q = p->next;
	p->data = q->data;
	p->next = q->next;
	free(q);
}

LNode *inverseLink(LNode *head)
{
	assert(head != NULL);
	LNode *p, *q, *r;
	p = head;
	q = p->next;
	while (q != NULL)
	{
		r = q->next;
		q->next = p;
		p = q; 
		q = r;
	}
	head->next = NULL;
	head = p;
	return head;
}

int main()
{
	LNode *head = CreateLink(5);
	head=inverseLink(head);  // 这里要对head重新进行写，函数里面对head并不保存。

	system("pause");
	return 0;
}