Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Example 1:
Input: [1,3,5,6], 5
Output: 2
Example 2:
Input: [1,3,5,6], 2
Output: 1
Example 3:
Input: [1,3,5,6], 7
Output: 4
Example 4:
Input: [1,3,5,6], 0
Output: 0
没啥好说的。。
class Solution {
public int searchInsert(int[] nums, int target) {
if(nums == null || nums.length == 0) {
return 0;
}
for(int index=0;index<nums.length;index++) {
if(nums[index] >= target) {
return index;
}
}
return nums.length;
}
}