题目描述
1672. 最富有客户的资产总量
解法:
没啥巧解,就是
O
(
n
∗
m
)
\mathcal O(n*m)
O(n∗m) 的方法
class Solution {
public:
int maximumWealth(vector<vector<int>>& accounts) {
int max_num = INT_MIN, ans = 0;
for (auto row: accounts)
{
int tmp = accumulate(row.begin(), row.end(), 0);
max_num = max(max_num, tmp);
}
return max_num;
}
};